Question

A piece of sodium weights 0.023 gram the number of atoms present in it are

Answer 1

It is the piece of sodium that weights the Fran at number of stand present it...❤️

Answer 2

Given:

Mass of sodium= 0.023 g

To find:

Number of atoms present in 0.023g

Solution:

According to Avagadro's law, each mole of an element has 6.022×10²³  atoms. So, 1 mole of sodium = 6.022 × 10²³ atoms

Number of moles in 0.063 g of sodium = given mass / molar mass

Moles of sodium = 0.023/23

Moles of sodium in 0.063g of Na = 0.001

Therefore, the number of atoms in 0.023g of Na = 0.001 × 6.022 × 10²³

= 0.006022× 10²³

= 6.022 × 10²⁰ atoms

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