a piece of Steel floats in Mercury the specific gravity of the mercury and steel are 13.6 and 7.8 respectively for covering the whole piece some water is filled above the mercury what part of the piece is inside the mercury
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Answer: 0.5
Explanation:
For flotation,
weight of the body = weight of the liquid displaced portion of the weight immersed in the liquid
ρ₁v₁g=ρ₂v₂g
Where,ρ is the density, v is the velocity and g is the acceleration due to gravity.
specific gravity is the ratio of density of a substance to the density of relative substance.
⇒ρ₁v₁g=ρ₂v₂g
⇒7×v₁=13.6×v₂
The fraction of volume of metal immersed under mercury is :
⇒v₂/v₁=7/13.6=0.5
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