Question

A piece of stone has a mass of 30g in air nad 18g in water. Calculate the volume of the stone if the density of water is 1g/cm^3

Answer 1

Answer:

Explanation:

Volume of the stone is the volume of water displaced by the stone

Now ,

Loss in weight of the object upon submersing = weight of the water displaced

Loss in wt. = wt. in air - wt. in water = 30g - 18g = 12g

=> wt. of water displaced = 12g

Density of water = Wt. of displaced water/vol. of water displaced

1g/cm^3 = 12g/V

=> Volume of water displaced = 12cm^3

volume of water displaced = volume of the stone

=> volume of the stone = 12cm^3 = 12ml

Answer 2

Explanation:

volume of the stone is 12 ml