Question

a piece of stone is thrown vertically upward with a speed of 30m/s. what the maxi mum that it reached? how high it will be after 2s? g=10m/s^-2​

Answer 1

answer=22.5

solution step by step

Given : u=30 m/s θ=45

o

Maximum height reached H=

2g

u

2

sin

2

θ

(sin

2

45

o

=0.5)

∴ H=

2×10

30

2

×0.5

=22.5 m