Question

A piece of stone of mass 15.1 g is first immersed
in a liquid and it weighs 10.9 gf. Then on
immersing the piece of stone in water, it weighs
9.7 gf. Calculate :
(a) the weight of the piece of stone in air,
(b) the volume of the piece of stone,
(c) the relative density of stone,
(d) the relative density of the liquid.​

Answer 1

Answer:

Weight in air = 15.1 gf

loss of weight of stone in water = 15.1-9.7 = 5.4gf

hence displaced volume of water = volume of stone = 5.4 cc

relative density of stone = mass/volume = 15.1/5.4 ≈ 2.8

loss of weight of stone in liquid = 15.1 - 10.9 = 4.2 gf

volume of displaced liquid = volume of displaced water = 5.4 c.c

weight of displaced liquid = loss of weight of stone in liquid = 4.2gf

relative density of liquid = mass/volume = 4.2/5.4 = 0.78

Explanation: