Question

A piece of stone of mass m is sliding down a smooth
ice surface. Standing on the same surface, a boy of
mass M picks up the stone. Find the initial velocity accquired by the boy
​

Answer 1

Explanation:

Let velocity of the stone is u .Momentum of stone is =muMomentum of the boy of mass M is =0 (before catching the stone)When the boy of mass M catches the stone ,let their common velocity be v.Momentum of the( boy+stone ) after the boy catches the stone is =(m+M)v...2Applying conservation of momentumfor the( stone +boy) system Initial momentum of the( boy +stone ) is =mu+0=muFinal momentum of the( boy +stone ) is =(m+M)vInitial momentum of the( boy +stone )=Final momentum of the( boy +stone )mu=(m+M)vv=mu(m+M)

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