Question

A piece of tarpaulin is in the form of a quadrilateral, where one of its diagonals is 20m long.
The two vertices on either side of these diagonal are 6m and 7m away. The area of the tarpaulin is:

Answer 1

Answer:

130m^2

Step-by-step explanation:

area of triangle ABD = 1/2 base *hight

= 1/2*20*7m^2

= 70 m^2

area of triangle BCD = 1/2*20*6 m^2

= 60 m^2

so the area of tarpaulin = area of ABD

+ area of BCD

answer = 70+60 m^2

= 130 m^2

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