Question

A piece of wire 11 cm long is bent into the form of an arc of a circle subtending an angle of 45 degree at its centre. find the radius of the circle

Answer 1

Heya,

According to the question,

The perimeter of arc will be = 11cm

Angle substended at the centre of the circle = 45°

Therefore,
We will use the formula,

theta/360° × 2πr. = circumference of arc

So,

45°/360° × 2×22/7×r = 11

1/8 × 2 × 22/7 × r = 11

r = 11×7×8/44

r = 7×8/4

r = 7×2

r = 14cm

So, radius of circle is 14 cm


Hope this helps....:)

Answer 2

Answer:

According to the question,

The perimeter of arc will be = 11cm

Angle substended at the centre of the circle = 45°

Therefore,

We will use the formula,

theta/360° × 2πr. = circumference of arc

So,

45°/360° × 2×22/7×r = 11

1/8 × 2 × 22/7 × r = 11

r = 11×7×8/44

r = 7×8/4

r = 7×2

r = 14cm

So, radius of circle is 14 cmAccording to the question,

The perimeter of arc will be = 11cm

Angle substended at the centre of the circle = 45°

Therefore,

We will use the formula,

theta/360° × 2πr. = circumference of arc

So,

45°/360° × 2×22/7×r = 11

1/8 × 2 × 22/7 × r = 11

r = 11×7×8/44

r = 7×8/4

r = 7×2

r = 14cm

So, radius of circle is 14 cm

Step-by-step explanation: