Question

A piece of wire 3 ÷4 m long was cut into three pieces. the first piece was 3 ÷20 m long, while the length of the second piece was 5÷3 of the first. how long was the third piece.?

Answer 1

first (3/20)*75
second 5/3*(3/20)*75
third be x
sun has to be 75
x = 45

Answer 2

3/4= total length
3/20=1st piece
3/20*5/3=2nd piece
15/60 = 1/4
thus, 3rd piece =(3/4)-(3/20+1/4)
= 3/4- 8/20= (15-8)/20 =7/20 m

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