Question

a piece of wire in the form of a equilateral triangle of side 3.14 cm is bent into a ring with no loss in wire. find the diameter of the ring.

Answer 1

Perimeter of equilateral triangle =3*side

Here, perimeter =3*3.14=9.42

Circumference of ring =πd

9.42/3.14=d

3=diameter


OR

9.42*7/22=diameter

=2.9972..

Answer 2

Side of triangle = 3.14 cm
Perimeter of triangle = 9.42 cm

Circumference of circle = Perimeter of triangle
C = 9.42 cm
2πr = 9.42
πd = 9.42
d = 942/100 * 7/22
d = 2.99 cm (approx.)
d = 3 cm (approx.)