A piece of wire is bent in the shape of an equilateral triangle each of whose sides measures 8.8cm.this wire is rebent to form a circular ring. what is the diameter of the ring
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the triengle is equilateral ant each side is 8.8cm.
so the circumference of the triangle is =(3*8)=24.
let us consider the radius of circle is=r,
as formlla, circmference of circle is =2*3.14*r;
and 2*3.14*r=24;
or, r=24/(2*3.14)
or, r=3.82.
or, 2r=7.64=diametre of ring.
so the circumference of the triangle is =(3*8)=24.
let us consider the radius of circle is=r,
as formlla, circmference of circle is =2*3.14*r;
and 2*3.14*r=24;
or, r=24/(2*3.14)
or, r=3.82.
or, 2r=7.64=diametre of ring.
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