a piece of wire is bent in the shape of an equilateral triangle each of whose sides measures 8.8 cm. the wire is rebent to form a circular ring. what is the diameter of the ring
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Answer:
26.4 cm
ONE SIDE OF EQUILATERAL TRIANGE =8.8cm
THEREFORE PERIMETER OF TRIANGLE = 8.8×3
=26.4cm
AS THE WIRE USED TO MAKE CIRCLE IS SAME , THEREFORE THE CIRCUMFERENCE OF CIRCLE WILL BE SAME AS PERIMETER OF TRIANGLE
CIRCUMFERENCE OF CIRCLE = 26.4cm
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