A piece of wire is bent in the shape of an equilateral triangle of each side 6.6cm .it is rebent to form a circular ring. What is the diameter of the ring.
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perimeter of triangle=3a
= 3× 6.6
=19.8 cm
circumference = 2pi r
19.8 = 2×22/7×r
19.8×7/2×22=r
r=3.15
d =2r
=2×3.15
=6.3cm
= 3× 6.6
=19.8 cm
circumference = 2pi r
19.8 = 2×22/7×r
19.8×7/2×22=r
r=3.15
d =2r
=2×3.15
=6.3cm
Anonymous:
hii
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