Question

a piece of wire is bent in the shape of an equilateral triangle of each side 6.6cm. it is rebent to form a circular ring. what is the diameter of the ring?

Answer 1

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Perimeter of equilateral triangle(P) = 3a
a=Lt. of side=6.6 cm
=> P= 19.8 cm
Now,
P = circumference of circular ring
P =2πR
19.8 =2×3.14×R
R=3.15 cm
diameter=2R=6.3 cm

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