A piece of wire is bent in the shape of an equilateral triangle of side 4.4 cm is this wire is bent to form a source of a circle find the radius and the area of a circle
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as it is the equilateral triangle
so perimeter of the triangle is a+b+c
perimeter = 4.4+ 4.4+4.4
perimeter=13.2 cm
circumfurrnce of the circle = perimeter of the triangle
2pier=13.2
2×22/7×r=13.2
r=13.2×7/22×2
r=0.6*7/2
r=0.3×7
r=2.1cm
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so perimeter of the triangle is a+b+c
perimeter = 4.4+ 4.4+4.4
perimeter=13.2 cm
circumfurrnce of the circle = perimeter of the triangle
2pier=13.2
2×22/7×r=13.2
r=13.2×7/22×2
r=0.6*7/2
r=0.3×7
r=2.1cm
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