a piece of wire is redrawn by pulling it until it is its length is doubled compare the new resistance with the original one
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Answer:
Volume = Area of cross-section x Length
∴ V = A'L' = AL
or A'A = LL' = L2L = 12 [∵ L' = 2L]
∴ Ratio of the resistances are,
R'R = ρL'A'ρLA = L'L× AA' = 21×21 = 4
i.e., R' = 4R
Thus, the new resistance is four times the original resistance.
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When
becomes
, A becomes
. New resistance,
(where
is the original resistance). <br> Since the two lamps are in parallel, total power,
<br> Resistance,
<br> Current,
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