Question

a piece of wire mesh of width 66 cm is rolled along the width to form a cylindrical tree protector of a certain height. iF 7986 cm area of wire mesh is used then what is the height of the tree protector

Answer 1

Step-by-step explanation:

width of wire mesh=66cm which is also the perimeter of cylindrical tree protector

$2\pi \: r = 66 \\ 2 \times \frac{22}{7} \times r = 66 \\ r = 66 \times \frac{7}{22} \times \frac{1}{2} \\ r = 10.5cm$

it is given that Area = 7986 cm^2

$lateral \: surface \: area \: of \: cylinder = 2\pi \: rh \\ 7986 = 2 \times \frac{22}{7} \times 10.5 \times h \\ 7986 = 44 \times 1.5 \times h \\ h = \frac{7986}{44 \times 1.5} \\ h = 121$

So height =121 cm

Answer 2

Step-by-step explanation:

hope it will help you. answer is correct.