A piece of wire of length 108 cm is bent to form
a semicircular arc bounded by its diameter.
Find its radius and enclosed area.
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Answer:
Length of wire = 108 cm
Let r be the radius of the semicircle
πr+ 2r = 108
⇒ r(π + 2) = 108 ⇒ r = ((22/7) + 2) = 108
⇒ (36/7)r = 108 ⇒ r = (108 × 7)/36 = 27 cm
Area = πr2 /2 = (22/(7 × 2)) × 21 × 21 = (1386/2) cm2
= 693 cm2
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