Question

A piece of wire of length 12.8cm is bent to form a square. Find the area of the
square formed.

Answer 1

Answer:

Given

Length of wire=12.8 was bent to make a square

Find area of square

As we know that square has four equal sides

12.8÷4= 3.2

Each side is 3.2

And area of square formula is side×side

3.2×3.2=10.24

Answer 2

AnswEr :

⋆Reference of Image is shown in Diagram

$\normalsize\sf\underbrace{\qquad\red{ Let \: it \: be \: Wire \: to \: be \: bent \: \quad}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(3.8,1.2){ 12.8\:cm }\end{picture}$

$\normalsize\sf\underbrace{ \qquad\red{ Let \: it \: be \: the \: square \: formed} \qquad}$

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.7,3){\large{A}}\put(7.2,2){\mathsf{\large{x cm}}}\put(7.7,1){\large{B}}\put(9,0.7){\matsf{\large{x cm}}}\put(10.6,1){\large{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){2}}\put(10.5,1){\line(0,3){2}}\put(8,3){\line(3,0){2.5}}\put(10.6,3){\large{D}}\end{picture}$

$\normalsize\bullet\:\sf\ Let \: the \: side \: of \: square \: be \: \bf\ x \: cm$

$\rule{200}2$

$\underline{\bigstar\:\textsf{According \: to \: the \: question \: now:}}$

$\normalsize\twoheadrightarrow\sf\ Length \: of \: wire = Perimeter \: of \: square$

$\normalsize\twoheadrightarrow\sf\ 12.8 = 4 \times\ side$

$\normalsize\twoheadrightarrow\sf\ 12.8 = 4 \times\ x$

$\normalsize\twoheadrightarrow\sf\ x = \frac{\cancel{12.8}}{\cancel{4}}$

$\normalsize\twoheadrightarrow\sf\ x = 3.2$

$\rule{170}2$

$\normalsize\star{\boxed{\sf{Area \: of \: square = (side)^2 }}}$

$\normalsize\twoheadrightarrow\sf\ Area_{sq} = (x)^2$

$\normalsize\twoheadrightarrow\sf\ Area_{sq} = (3.2)^2$

$\normalsize\twoheadrightarrow\sf\ Area_{sq} = 3.2 \times\ 3.2$

$\normalsize\twoheadrightarrow\sf\ Area_{sq} = 10.24$

$\large\twoheadrightarrow{\underline{\boxed{\sf \green{Area_{sq} = 10.24cm^2}}}}$