Question

A piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length ? Calculate the resistance of the wire in the new situation?​

Answer 1

hyy dude

Given resistance = R1 = 20 ohm

Let length of the wire = L

Therefore , new length of the wire = 2 L

Since , when the length is doubled , cross sectional area of the wire becomes half.

Therefore , new resistance = R = 2 L / ( A / 2 ) =4 L / A

R = 4 × 20 ( since , L / A resistance )

R = 80 ohm .

May this helps you

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Answer 2

Answer:

heya mate....(◕ᴗ◕✿)

Explanation:

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