A piece of wire of resistance 20 Ohm is drawn out so that its length is increased to twice its original length calculate the resistance of the wire in the new situation.
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Does are of cross section be halved
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20 = rho × L/A
ATQ
20 = rho × 2L/A
10 = rho × L/A
THEREFORE THE NEW RESISTANCE IS 10 OHM
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