Question

A piece of wire of resistance 6ohm is connected to battery of 12V. Find the amount of current flowing through it. Now, the same wire is redrawn
by stretching it to double its length, find the resistance of the redrawn wire​

Answer 1

Answer:

V=IR

I=12/6

I=2 A

Resistance is directly proportional to Length of Conductor

So, if if length is doubled then resistance will also be doubled.

p=RA/L,   where p is resistivity of wire.

Thus, new resistance would be 12 ohm

Answer 2

Explanation:

V=IR

I=12/6

I=2 Ampere

if length of wire is doubled by stretching then the area becomes half

l'=2l and a'=a/2

R'=rho×l'/a'

R'=rho×2l

a/2

R'=rho×4l

a

R'=4×R. (R=rho×l)

a

R'=24 ohm