Question

a piece of wire of resistance R cut in to five equal parts .these parts are then connected in parallel .if equivalent resistance of this R^

Answer 1

When cut into 5 pieces, resistance of each part is R/5.

So, equivalent resistance of the 5 pieces when connected in parallel is, 1/R1 = 5/R + 5/R + 5/R + 5/R + 5/R

=> R1 = R/25

So, required ratio is, R : R1 = 25 : 1

Answer 2

Let the Total Resistance be R.

When cut into 5 equal parts,
each part has R/5 Resistance.

When connected in Parallel,
1/R^ = 5/R + 5/R +5/R+5/R + 5/R
i.e;

1/R^ = 25 /R
Therefore R ^ = R/25

Is the question incomplete though?

I hope this helped.