A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R//R' is :
Answers
Answer:
ये कोनसे सत्संदर्द का प्रर्शन हे??
Answer:
The ratio R/R' is 25 : 1.
Explanation:
Given that:
A piece of wire of resistance R is cut into five equal parts.
These parts are then connected in parallel.
The equivalent resistance of this combination is R'.
To Find:
The ratio R/R'.
We know that:
In parallel combination.
R' = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + ...
Where,
R' = Equivalent resistance
1/R₁, 1/R₂, 1/R₃, 1/R₄ are the resistance at different position.
Finding the equivalent resistance if R is cut into five equal parts:
⇢ 1/R' = 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5)
⇢ 1/R' = 5/(R/5)
⇢ 1/R' = (5 × 5)/R
⇢ 1/R' = 25/R
⇢ R' = R/25
⇢ R = 25R'
Finding the R/R':
R : R'
25R' : R'
Cancelling R'.
25 : 1
Hence,
The ratio R/R' is 25 : 1.