A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R/R' will be what?
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We know that resistance is directly proportional to the length of the wire, now when the length is divided into 5 then resistance becomes 1/5.
Now when we add them in parallel the equivalent resistance is
1/R'= 5/R +5/R +5/R+ 5/R +5/R
1/R'= 25/R
R' =R/25.
Ratio of R/R' = R/ (R/25)
= 25:1.
Hope this helps.
Now when we add them in parallel the equivalent resistance is
1/R'= 5/R +5/R +5/R+ 5/R +5/R
1/R'= 25/R
R' =R/25.
Ratio of R/R' = R/ (R/25)
= 25:1.
Hope this helps.
10LMessi:
How did it come as 1/R
Sory now knew it ,,ok so it was bcus its in parallel
I didnt udstnd the last step
That R/R
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