compare the power used in 2ohm resistor in each case:
6V battery in series with 1ohm and 2ohm resistors
4V battery in parallel with 12ohm and 2ohm resistors
Answers
Answered by
6
Power = V^2/R
Power in First case = 6^2 / (1+2)
= 36/3= 12 Watts
Power consumed in second case = 4^2/(12*2/(12+2))
16/( 24/14) = 28/3 Watts
Hope this helps.
Power in First case = 6^2 / (1+2)
= 36/3= 12 Watts
Power consumed in second case = 4^2/(12*2/(12+2))
16/( 24/14) = 28/3 Watts
Hope this helps.
Answered by
3
Answer: P1/P2 = 3/2
Explanation:
V1 = 6V
R1 = 2ohm
P1 = V^2/ R
= 36/2
= 12W
V2 = 4V
R2 = 2 ohm
P2 = V^2/R
= 16/2
= 8W
~ P1/P2 = 12/8 = 3/2
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