Question

A piece of wireis bent to form a rectangle of area 72 cm™².If the length is twice its breadth.Find the length of the wire
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Answer 1

Answer :

The required length of the wire = 36 cm

Step-by-step explanation :

Given :

• A piece of wire is bent to form a rectangle of area 72 cm²
• the length is twice its breadth

To find :

the length of the wire

Solution :

Let L cm be the length of the rectangle and B cm be the breadth of the rectangle.

 L = 2B

Area of the rectangle = length × breadth

 72 cm² = L × B

 72 = 2B × B

 2B² = 72

  B² = 72/2

  B² = 36

  B = √36

  B = 6 cm

The breadth of the rectangle = 6 cm

The length of the rectangle = 2(6) = 12 cm

we have to find the length of the wire. Let it be "l cm"

Since the wire is bent to form a rectangle, the length of the wire is equal to the perimeter of the rectangle.

     

So, finding the perimeter of the rectangle :

➙ Perimeter of the rectangle = 2(Length + breadth)

➙ Perimeter of the rectangle = 2 ( L + B)

➙ Perimeter of the rectangle = 2 (12 + 6)

➙ Perimeter of the rectangle = 2 (18)

➙ Perimeter of the rectangle = 36 cm

The length of the wire is equal to the perimeter of the rectangle.

Therefore, the length of the wire = 36 cm

Answer 2

$\huge\bf{Solution}$

Step by step explaination:-

As they given ,

Area of rectangle is 72cm²

And given Length is twice its breadth So,

Length is 2x

Breadth is x

Formula:- Area of rectangle =length× breadth

So,2

72cm² = 2x × x

72cm² = 2x²

x² = 36

x = 6cm

So length of rectangle is 2x = 12cm

Breadth of rectangle is x = 6cm

Since wire is bent to rectangle Its length should be equal to perimeter

Perimeter of rectangle = 2(l+b)

So, perimeter = 2(6+12)

Perimeter = 2(18)

Perimeter = 36cm

So,length of rectangle is 36cm

More to know:-

Perimeter of square = 4a

Perimeter of equilateral triangle = 3a

Perimeter of scalene triangle = a+b+c

Area of sqaure = s²

Area of equilateral triangle = 1/2 b×h