A piece of wood weighs 74 g in air. A lead sinker which weighs 32 g in water is attached to the wood to sink it in water. If the total weight of the wood and the sinker in water is 13.5 g, find the relative density of the wood.
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Question
A block of wood weighs 60g in air. A lead sinker weighs 70g in water. The sinker is attached to the wood and
both together weigh 65g in water. Find the relative density of the wood
Solution
() 70
=
70
(− )
()= 60
=
60
()
() + ()−( + ) = 65
Thus,
()
70
( − )
+ ()
60
()
− (
70
()
+
60
()
) = 65
()
70
()
+ ()
60
()
− (
70
()
+
60
()
) = 65
70 − 60 (
− 1) = 65
60 (
− 1) = 5
− 1 =
5
60
=
1
12
= 1 +
1
12 =
13
12
The relative density of the wood is
=
12
13 = 0.923
Answer provided by SHREYASH.
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