Question

a piece of work can be done by 2 men and 5 boys in 5 days. 1/3rd of the work can be done by 3 men and 4 boys in 3 days. how long will it be required by 9 men to do the same work. ​

Answer 1

Answer:

Let the amount of work done by a Man alone in a day be M and by a Boy alone be B

Given, 2 men and 5 boys together can finish a piece of work in 4 days

Amount of work they can do in one day 2M+5B =

4

1

-- (1)

Similarly, 3M+6B=

3

1

--- (2)

Solving equations (1) and (2), we get B=

36

1

Substituting B in equation (2), we get M=

18

1

Hence, one man alone will take 18 days to do the work and one boy will take 36 days.