Question

A piece of work has to be completed in 60 days, a number of men are employed but it is found that only half of the work is done in 40 days, then an additional 30 men were joined to complete the work on time. Initially how many men are there to work?

Answer 1

Answer:

30 Men

Step-by-step explanation:

Let say initially Men were employed  M

Let say one Man one day work = x

Then work done by M in 40 days =  M * 40 * x

Work done by M+30 in (60-40) 20 days =  (M+30)*20*x

Both are equal as half work was earlier done and remaining half was later done

40Mx = 20Mx + 600x

20Mx = 600x

M = 30

so initially there were 30 Men

Answer 2

Answer:

initially 20 men are there to work

Step-by-step explanation:

We Have given in the question as work has to be completed in 60 days, half of work done in 40 days, then additional 30 men were joined to complete the work.

Let the number of Men = X

number of men day required to complete half of of the part of work = 40x where x is the no of Men employed.

The remaining half part of the work is completed when 30 more men were employed in 60 - 40 = 20

So, Now solve this equation as

40x = 20 ( x + 20 )

40x = 20x + 400

20x = 400

x = 400 / 20

x 20

Hence the required answer is 20

therefore, initially 20 men are there to work