Question

A piggy bank contains fifty 50 paise coins, forty ₹1 coins, twenty ₹ 2 coins and twenty ₹ 5 coins. If it is equally likely that one of the conch will fall out when the bank is turned upside down then what is the probability that the coin (i) will be a 50 paise coin. (ii) will not be a ₹ 5 coin.
(Class 10 Maths Sample Question Paper)

Answer 1

Solution:
Given :

Number of 50 paise coins= 50
Number of ₹1 coins=40
Number of ₹2 coins=20
Number of ₹5 coins=20

Total number of coins in a piggy bank= 50 +40+20+20= 130.

(i) P(getting a 50 paise coin) = number of 50 paise coins/total number of coins
P(getting a 50 paise coin) =50/130= 5/13

(ii) P(not getting a ₹5 coin) = number of[ 50 paise coins+ ₹1 coins + ₹2 coins] /total number of coins
P(not getting a ₹5 coin) =(50+40+20)/130= 110/130= 11/13


HOPE THIS WILL HELP YOU...

Answer 2

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PROBABILITY PROBLEM SOLVING !

TO FIND : (i) will be a 50 paise coin. (ii) will not be a ₹ 5 coin.

We are having total number of coins = 50 + 40 + 20 + 20 = 130

So, one coin can be chosen out of 130 coins in 130 ways.

Total no. of elementary events = 130

i) There are 50 fifty paise coins out of which one can be chosen in 50 ways.

Therefore, Probability that a 50 paisa coin will fall = 50/130 =  5/13

ii) Probability : will not be a ₹ 5 coin = No. of 50 paise coins + 1 Rs coins + 2 Rs coins / Total no. of coins.

⇒ 50 + 40 + 20 = 110

⇒ 110 / 130

⇒ 11/13.

FINAL ANSWERS :-

• (i) will be a 50 paise coin = 5/13

• (ii) will not be a ₹ 5 coin = 11/13