Question

a piggy bank contains hundred 50 paise coins, fifty 1 rupees coin twenty 2rupees coin and ten 5 rupees coins if it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell (1) will be of value more than rupees 1​? here we need to find probability of (1)​

Answer 1

Answer:

1/6

Step-by-step explanation:

(1) Given,

50 paise coins = 100

1 Rs coin = 50

2 Rs coin = 20

5 Rs coin = 10

Total number of possible outcomes=100+50+20+10=180

Hence, probability is given by

P(event)=No.of favourable outcomes/Total number of possible outcomes

$= \frac{20 + 10}{180} \\ \frac{30}{180} \\ = \frac{1}{6}$

Answer 2

Answer:

1/6

Step-by-step explanation:

as given in photo hope this will help you