Question

A piggy bank contains hundred 50p coins, fifty ₹ 1 coins, twenty `₹ 2 coins and ten `₹ 5 coins. If it is equally likely that

one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a ₹ 50 p

coin? (ii) will not be a ₹ 50p coin? (iii) will be a ₹ coin?​

Answer 1

Answer:

(i) Given: Number of 50 paise coins = 100

Number of 1 rupee coins = 50

Number of 2 rupee coins = 20

Number of 5 rupee coins = 10

So, total number of coins = Total number of coins = 100 + 50 + 20 + 10  = 180

Total number of possible outcomes of a coin will fall out = 180

Number of 50 p coins = 100

Number of favourable outcomes relating to  fall out of a 50 p coin = 100

Now, P(of getting a 50 p coin)

Number of favourable outcomes ÷ Total number of possible outcomes

$\frac{100}{180} = \frac{5}{9}$

(ii) P(not a 5 coin) = 1 – P(5 coin)

= $1 - \frac{10}{180}$

=$\frac{17}{18}$

Answer 2

Answer:

no of 50p coins=100

no of ₹1coin=50

no of ₹2coins=20

no of ₹5 coins=10

so total no of coins=180

p(50p coins) = no of favourable event/total no of event

=100/180, =5/9

ii) p(not 50 p coin) =1-5/9=4/9

hope you understand