Math, asked by sasikavir05gmailcom, 9 months ago

a piggy Bank contains hundred 50p coins, fifty 1 rupee coins, twenty 2 rupee coins and ten 5 rupee coins . if it is equally likely that one of the coins will fall out when the bank when turned upside down ,what is the probability that the coin a. will be a 50p coin ? b.will not be a 5 rupee coin?​

Answers

Answered by jothisree9
14

Answer:

a.5/9  b.17/18

Step-by-step explanation:

The total number of coins is = 100+50+20+10=180 coins

a.Number of 50p coins is 100

Thus probability of the 50p coin to fall = 100/180 = 5/9

b.Not a 5rs coin = 100+50+20

since only 10 5rs coins are present

Thus probability that the coin is not a 5rs coin = 170/180 => 17/18

 

Answered by aravindkumar4456
1

Total no. of coins = 100 + 50 + 20 + 10 = 180

Total no. of coins = 100 + 50 + 20 + 10 = 180P(E)

= (Number of favourable outcomes/ Total number of outcomes)

(i) Total number of 50 p coin = 100

P (50 p coin) = 100/180 = 5/9 = 0.55

(ii) Total number of ₹5 coin = 10

P (₹5 coin) = 10/180 = 1/18 = 0.055

∴ P (not ₹5 coin)

= 1 – P (₹5 coin)

= 1 – 0.055

= 0.945

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