a piggy Bank contains hundred 50p coins, fifty 1 rupee coins, twenty 2 rupee coins and ten 5 rupee coins . if it is equally likely that one of the coins will fall out when the bank when turned upside down ,what is the probability that the coin a. will be a 50p coin ? b.will not be a 5 rupee coin?
Answers
Answered by
14
Answer:
a.5/9 b.17/18
Step-by-step explanation:
The total number of coins is = 100+50+20+10=180 coins
a.Number of 50p coins is 100
Thus probability of the 50p coin to fall = 100/180 = 5/9
b.Not a 5rs coin = 100+50+20
since only 10 5rs coins are present
Thus probability that the coin is not a 5rs coin = 170/180 => 17/18
Answered by
1
Total no. of coins = 100 + 50 + 20 + 10 = 180
Total no. of coins = 100 + 50 + 20 + 10 = 180P(E)
= (Number of favourable outcomes/ Total number of outcomes)
(i) Total number of 50 p coin = 100
P (50 p coin) = 100/180 = 5/9 = 0.55
(ii) Total number of ₹5 coin = 10
P (₹5 coin) = 10/180 = 1/18 = 0.055
∴ P (not ₹5 coin)
= 1 – P (₹5 coin)
= 1 – 0.055
= 0.945
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