How much load is lifted if an effort of 25 kg is applied to a simple machine having velocity ratio of 4 and efficiency 75%?
Answers
Answered by
16
Answer:
Explanation:
Load = effort ×advantage
So advantage =efficient %×velocity ratio / 100 = 3
Now
Load = 25 ×3 = 75 answer by
Jnb classes gr.noida fb page
Answered by
0
Answer:
Explanation:
75
Similar questions