Question

A pipe can empty a tank in 15h and another pipe can empty it in 10h. if both the pipes are opened simultaneously, find the time in which a full tank is emptied.​

Answer 1

Step-by-step explanation:

pipe A can empty tank in 15 hr so in 1 hr it can empty 1/15 part of tank

pipe B can empty tank in 10 hrs,so in 1 hr it can empty 1/10 part of tank

if both pipes are opened then amount of tank can be emptied in 1 hr = (1/15 + 1/10)

=1/6

the two pipes can empty 1/6 part in one hour...to empty the whole tank it requires 6 hours

The total time required is 6 hrs

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