Question

a pipe can fill tank in x hrs another can empty it in y hours. if the tank is 1/3 rd full then the number of hours in which they will together fill it in is

Answer 1

Answer:

Step-by-step explanation:

Nothing further can be done with this topic. Please check the expression entered or try another topic.

x h s , y h , 1 3 , r \d , h

Answer 2

Part filled in 1 hour by both the pipes = 1/x - 1/y = (y-x)/xy
As tank is 1/3 full, so remaining to be filled=1 - 1/3 = 2/3
Hence required time to fill 2/3 tank = (2/3) / (y-x)/xy = 2xy/[3(y-x)] hours.