Question

A pipe of length 35 m. is divided into two parts in the ratio 3:4 . Find the length of each part.​​

Answer 1

Answer:

total length = 35m

ratio of two parts = 3:4

length of each part = 3/7 × 35 =15m,4/7 × 35 = 20m

Answer 2

$\begin{gathered} \\ \Large{\bf{\green{\underline{AnSwEr\::}}}} \\ \end{gathered}$

The first part of the pipe = 15 m

The second part of the pipe = 20 m

$\begin{gathered} \\ \Large{\bf{\red{\underline{GiVeN\::}}}} \\ \end{gathered}$

• Length of the pipe = 35 m
• The ratio of two pipes = 3 : 4

$\begin{gathered} \\ \Large{\bf{\purple{\underline{To \: FiNd\::}}}} \\ \end{gathered}$

• The length of each part..

$\begin{gathered} \\ \Large{\bf{\pink{\underline{SoLuTiOn\::}}}} \\ \end{gathered}$

Let the first part be 3x and second part be 4x

Sum of the two parts of the pipe = 35 m

⇒3x + 4x = 35 m

⇒7x = 35 m

⇒x = 35 m ÷ 7

⇒x = 5 m

The first part of pipe = 3x = 3 × 5 m = 15 m

The second part of pipe = 4x = 4 × 5 m = 20 m