Math, asked by Ramakantbhagat61, 4 months ago

A pipe of length 35 m. is divided into two parts in the ratio 3:4 . Find the length of each part.​

Answers

Answered by Anonymous
2

The line is divided in to two parts with the ratio 4:3

Lets take the value x and then calculate the total length of each part.

Line is divides into two part 4x and 3x.

The length of line is 35 cm.

4x+ 3x = 35,

Now solve the algebric equation,

7x = 35,

x= 35/7,

x= 5,

We calculate the value of x,

Now put the value of x, in 4x and 3x

4x,

4x5 = 20 cm,

3x,

3x5=15 cm,

So the length of each part is 20cm and 15cm.

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Answered by StylusMrVirus
2

\begin{gathered} \\ \Large{\bf{\green{\underline{AnSwEr\::}}}} \\ \end{gathered}

  • The first part of the pipe = 15 m

  • The second part of the pipe = 20 m

\begin{gathered} \\ \Large{\bf{\red{\underline{GiVeN\::}}}} \\ \end{gathered}

  • Length of the pipe = 35 m
  • The ratio of two pipes = 3 : 4

\begin{gathered} \\ \Large{\bf{\purple{\underline{To \:  FiNd\::}}}} \\ \end{gathered}

  • The length of each part..

\begin{gathered} \\ \Large{\bf{\pink{\underline{SoLuTiOn\::}}}} \\ \end{gathered}

  • Let the first part be 3x and second part be 4x

  • Sum of the two parts of the pipe = 35 m

⇒3x + 4x = 35 m

⇒7x = 35 m

⇒x = 35 m ÷ 7

⇒x = 5 m

The first part of pipe = 3x = 3 × 5 m = 15 m

The second part of pipe = 4x = 4 × 5 m = 20 m

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