A pipe of length 35 m. is divided into two parts in the ratio 3:4 . Find the length of each part.
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The line is divided in to two parts with the ratio 4:3
Lets take the value x and then calculate the total length of each part.
Line is divides into two part 4x and 3x.
The length of line is 35 cm.
4x+ 3x = 35,
Now solve the algebric equation,
7x = 35,
x= 35/7,
x= 5,
We calculate the value of x,
Now put the value of x, in 4x and 3x
4x,
4x5 = 20 cm,
3x,
3x5=15 cm,
So the length of each part is 20cm and 15cm.
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- The first part of the pipe = 15 m
- The second part of the pipe = 20 m
- Length of the pipe = 35 m
- The ratio of two pipes = 3 : 4
- The length of each part..
- Let the first part be 3x and second part be 4x
- Sum of the two parts of the pipe = 35 m
⇒3x + 4x = 35 m
⇒7x = 35 m
⇒x = 35 m ÷ 7
⇒x = 5 m
The first part of pipe = 3x = 3 × 5 m = 15 m
The second part of pipe = 4x = 4 × 5 m = 20 m
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