Question

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Answer 1

Answer:

1. -5 is a root

=> 2x² +px -15 = 0

=> 2(-5)² + p(-5)-15=0

=> 50-5p -15 = 0

=> 5p = 35

=> p = 7

now p(x²+x) + k =0

both equation has same roots..

put p=7 & x=-5

=> 7(25-5)+k = 0

=> k = -140

2. a) 2x² +3x + p =0

put p = -2

2x²+3x-2=0

b) 2x² + 3x -5 = 0

p= -5

c) p = 1

2x² + 3x+ 1 = 0

3. x²+kx+4

put k = 4

=>x²+4x+4

=> (x+2)²

4.3x²-px+5=0

p=8

3x²-8x+5=0

=>3x²-3x-5x+5

b) put p=-8

3x²+8x+5=0

3x²+3x+5x+5=0

Answer 2

Step-by-step explanation:

p=7

k=-140

i dont know

p=-5

i dont know

(x+2)square

p=8

p='8

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