Physics, asked by lmohanvictory, 6 hours ago

A piston cylinder contains 1.5 kg water at 200 kPa, 150°C. It is now heated in a process where pressure is linearly related to volume to a state of 600 kPa, 350°C. Find the final volume, the work and the heat transfer in the process.

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Answered by lionsgaming010
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Answer:

A spring loaded piston/cylinder contains 1.5 kg of air at 27C and 160 kPa. It is now heated to 900 K in a process where the pressure is linear in volume to a final volume of twice the initial volume. Plot the process in a P-v diagram and find the work and heat transfer.

Take CV as the air.

m₂ m₁ m; m(u₂-₁)=1Q2-1W₂

Process: P= A + BV => 1W₂ IP dV area=0.5(P₁ + P₂)(V₂-V₁)

State 1: Ideal gas.

V₁ mRT₁/P₁ 1.5x 0.287 300/160=0.8072 m³

Table A.7

u₁u(300) 214.36 kJ/kg

State 2: P₂V₂ mRT₂ so ratio it to the initial state properties

P₂V₂/P₁V₁=P₂2/P₁=mRT₂/mRT₁=T₂/T₁ =>

P2 P1 (T2/T1)(1/2)=160 (900/300) (1/2)-240 kPa

Work is done while piston moves at linearly varying pressure, so we get

1W₂=0.5(P₁ + P₂)(V₂ -V₁)=0.5x(160+240) kPa 0.8072 m³= 161.4 kJ Heat transfer is found from energy equation

1Q2 m(u₂-₁)+1W₂=1.5x(674.824-214.36)+161.4-852.1 kJ

Explanation:

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