A pit 4m long 4m wide and 2.8m deep is dug at the corner of a rectagular ground with dimentions 20m by 12m.if the earth taken out is spread evenly over the remaining area of the ground.Find the rise in the level of tge ground.
Answers
Answer:
Rise in level of ground = 0.2 m
Step-by-step explanation:
Given: Dimension of ground 20 m × 12 m
Dimension of pit which is dugged 4 m × 4 m × 2.8 m
To find : Rise in the level of ground.
Volume of Earth taken out from pit = Length × width × height
= 4 × 4 × 2.8
= 44.8 m³
volume of earth taken out = volume of earth spread
44.8 = volume of earth on ground - volume of
earth over pit
44.8 = 20 × 12 × h - 4 × 4 × h
44.8 = ( 240 - 16 ) × h
h = 0.2 m
Therefore, Rise in level of ground = 0.2 m
Answer: The rise in the level of the ground would be approximately 0.12 m.
Step-by-step explanation:
Given that,
Length of pit= 4m, width= 4m, and depth= 2.8m
Volume of earth taken out= 4*4*2.8 = 44.8 m^3
Dimension of the ground is 20m by 12m.
Area where the earth taken out is to be spreaded= 20*20 - 4*4
=> 400 - 16= 384 m^2
The rise in the level of the ground= earth taken out/area where earth is be spreaded.
So,
The rise in the level of the ground= 44.8/384 = 0.12 m (approx)