Physics, asked by parvinderyadav8263, 10 months ago

A pitcher with 1-mm thick porous walls contains 10 kg of water. Water comes to its outer surface and evaporates at the rate of 0.1 g s−1. The surface area of the pitcher (one side) = 200 cm2. The room temperature = 42°C, latent heat of vaporization = 2.27 × 106 J kg−1, and the thermal conductivity of the porous walls = 0.80 J s−1 m−1°C−1. Calculate the temperature of water in the pitcher when it attains a constant value.

Answers

Answered by MƦAttrαctívє
1

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<b>ℓ = 1mm = 10–3m m = 10kg A = 200cm2 = 2 × 10–2m2 Lvap = 2.27 × 106J/kg K = 0.80J/m-s-°C Read more on Sarthaks.com - https://www.sarthaks.com/63483/a-pitcher-with-1-mm-thick-porous-walls-contains-10kg-of-water

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Answered by suvarchalabkk
0

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