Question

A steel frame (K = 45 W m−1°C−1) of total length 60 cm and cross sectional area 0.20 cm2, forms three sides of a square. The free ends are maintained at 20°C and 40°C. Find the rate of heat flow through a cross section of the frame.

Answer 1

$\huge\bold\star{\underline{\underline{\mathcal\purple{Nmste}}}}\star$

$<b>$Refer To The Attachment

▌│█║▌║▌║▌│█║▌║▌║♥️

Answer 2

Answer:

thermal conductivity,K=45Wm⁻¹°c⁻¹

length,l=60cm=0.6m

area of cross section ,A=0.2cm²=0.2*10⁻⁴m²

initial temperatureT₁=40°c

final temperatureT₂=20°c

rate if flow of heat = Temperature differences/Thermal resistance

ΔΘ/Δt=ΚΑ(T₁₋T₂)/∫

ΔΘ/Δt=45*0.2*10⁻⁴(40-20)/0.6

=0.03W

Hope this helps u. Mark as the brainliest