a plan left 30 min late than its scheduled time and in order to reach the destination 1500km away in time it had to increase it's speed by 100km/hr from the usual speed . find its visual speed.
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Let the usual time taken by the aeroplane = x km/hr
Distance to the destination = 1500 km
Case (i)
Speed = Distance / Time = (1500 / x) Hrs
Case (iI)
Time taken by the aeroplane = (x - 1/2) Hrs
Distance to the destination = 1500 km
Speed = Distance / Time = 1500 / (x - 1/2) Hrs
Increased speed = 100km/hr
=[1500 / (x - 1/2)] - [1500 / x] = 100
= two value of x=-2.5, x=3
= its means 1500/3=500
Distance to the destination = 1500 km
Case (i)
Speed = Distance / Time = (1500 / x) Hrs
Case (iI)
Time taken by the aeroplane = (x - 1/2) Hrs
Distance to the destination = 1500 km
Speed = Distance / Time = 1500 / (x - 1/2) Hrs
Increased speed = 100km/hr
=[1500 / (x - 1/2)] - [1500 / x] = 100
= two value of x=-2.5, x=3
= its means 1500/3=500
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