The diameter of lower and upper end of bucket in the form of frustum of cone are 10cm and 30cm respectively and height is 24cm.find area of metal sheet used to makes the bucket.
Answers
Radius of the upper end of the frustum of cone( r1) = 15cm
Diameter of lower end of bucket = 10 cm
radius of the lower end of the frustum of cone( r2) = 5 cm
H of the frustum of Cone = 24 cm
Slant height of bucket ( L)= √(h² + (r1- r2)²
L =√24² + (15 - 5)² = √576 + 10²
L =√(576+(100)= √676 = 26cmL = 26 cm
Area of metal sheet require to make it = π(r1 + r2)L + πr1²
= 3.14(15 + 5) × 26 + π(5)²
= 3.14 × 20 × 26 + 25 × 3.14
= 3.14 (520+ 25)
= 545 × 3.14= 1711.3 cm²
Hence, the Area of metal sheet used to make the bucket is 1711.3 cm².
HOPE THIS WILL HELP YOU...
Given:
Diameter of the upper end = 30 cm
Diameter of the lower end = 10 cm
Height = 24 cm
To find:
Area
Solution:
Radius of the upper end of the cone = 15 cm
Radius of the lower end of the cone = 5 cm
In order to find the area,
The slant height should be calculated.
Slant height = √ ( h^2 + ( Radius of the upper end of the cone - Radius of the lower end of the cone )^2
√24^2 + ( 15 - 5 )^2
√576 + 10^2
Slant height = 26 cm
Area of the metal = Curved surface Area + Area of base of the cone.
Curved surface area = π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height
Area of the base = πr2^2
Hence,
π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height + πr2^2
3.14 ( 15 + 5 ) × 26 + π( 5 )^2
3.14 × 20 × 26 + 25 × 3.14
545 × 3.14
Area = 1711.3 sq.cm
Read more on Brainly.in - https://brainly.in/question/3116353