Question

a plane covered a distance of 630 miles in 6 hours . for the first part of the trip the average speed was 100 mph and for the second part of the tripvthe average speed was 110cmph.what is the time it flew at each speed?

Answer 1

the answer is 3 hrs for 100 mph & 3 hrs for 110 mph

Answer 2

Answer:

time = 3 hour

Step-by-step explanation:

let the distance covered in first part of the journey = d

therefore, the distance covered in the second part of journey = 630 - d

let the time taken for the first part of the journey be there for the time taken for the second part journey will become 6-t

from the first equation d = 100t

the second equation is 630 - D

= 110 (6-t)

substituting the value from the first equation we have

630 - 100t = 110 (6-t)

solving this gives t =3

show the plane flew the first part of the journey in three hour and the second part of the journey in 3 hours