A plane goes from Chicago to Columbus and then comes back. It takes the same time to travel in either ways. It leaves Chicago early in the morning at 6:44 a.m. as per the local time and reaches the destination - Columbus at 8:49 a.m. as per the local time. On the same day in evening, it leaves Columbus at 4:25 p.m. as per the local time and reaches the destination – Chicago at 4:38 p.m. as per the local time. Find the time that the plane takes to travel either ways.
Answers
Answer:
A plane goes from Chicago to Columbus and then comes back. It takes the same time
to travel in either ways. It leaves Chicago early in the morning 0644 LOCAL TIME
and reaches the destination Columbus at 0849 LOCAL TIME. In the same evening it
leave Columbus at 1625 hrs LOCAL TIME and reaches the destination at 1638
LOCAL TIME. Find the time that the plane takes to travel either way?
69 minutes
Asked by: Interview Candidate
Asked on: Jul 7th, 2005
Showing 1 - 3 of 3 Ans
priya
Answered On : Apr 22nd, 2006
205hrs and 13hrs. please if you get the correct answer mail me ok bye.
thiyagarajanganesan
Answered On : Aug 12th, 2006
If u r interested means give me the correct answers and steps to follow.it is very useful for entry level students.
ubron
Answered On : Jan 11th, 2007
The plane starts from Chichago at 6:44(Chichago local time). Let the time it takes to reach Columbus be x. It reaches Columbus at 8:49(Columbus local time) ,so the Chicago local time at that moment is 6:44+x. The duration of stay at Columbus is from 8:49 to 16:25 ie 7hrs 36mins.It leaves Columbus at 16:25 n reaches Chicago at 16:38(Chicago local time) taking x time again. So 6:44+x plus 7hrs 36mins plus x is 16:38(chicago local time).The duration between 6:44 and 16:38 is 9hrs 54mins. Therefore (9hrs 54mins) = (7hrs 36mins)+2x x= 1hr 9mins or 69mins.
Answer:
it is so much big I can't write