A plane has take off of 300km/hr.What is the acceleration if it is started from rest of 0.25 hour to take off
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Answered by
1
Answer:
Data: Initial velocity = 0km/h
Final velocity = 300km/h
Time = 0.25 h
Formula: a = final velocity - initial velocity / time
a = 300 - 0 /0.25
a = 300/0.25
a = 1200 m/s/s
Answered by
1
Answer:
we know acceleration(a)=change in velocity/time
here initial velocity=0
and final velocity=300km/hr
so change in velocity=300-0=300km/hr
thus acceleration (a)=300/0.25
=1200 km/ square hour
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