Question

A plane has take off speed of 300 km/h what is the acceleration inm/s of the olane if the plane start from rest and took 45 sec to take off

Answer 1

Explanation:

velocity=300into5/18

=500/9

a=v/t=500/9/45

=500/9(1/45)

=100/81

Answer 2

The acceleration of the plane is $1.852\ m/s^2$.

Explanation:

Initial speed, u = 0

Final speed, v = 300 km/h = 83.34 m/s

Time, t = 45 s

The acceleration is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{83.34}{45}\\\\a=1.852\ m/s^2$

The acceleration of the plane is $1.852\ m/s^2$.

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